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5u^2+15u+10=0
a = 5; b = 15; c = +10;
Δ = b2-4ac
Δ = 152-4·5·10
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*5}=\frac{-20}{10} =-2 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*5}=\frac{-10}{10} =-1 $
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